# In a template definition, unqualified names will no longer find members of a dependent base. For example,
template <typename T> struct B {
int m;
int n;
int f ();
int g ();
};
int n;
int g ();
template <typename T> struct C : B<T> {
void g ()
{
m = 0; // error
f (); // error
n = 0; // ::n is modified
g (); // ::g is called
}
};
You must make the names dependent by prefixing them with this->. Here is the corrected definition of C<T>::g,
template <typename T> void C<T>::g ()
{
this->m = 0;
this->f ();
this->n = 0
this->g ();
}
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